3.34 \(\int \frac {2 (-\frac {a}{b})^{2/3} C+C x^2}{a-b x^3} \, dx\)

Optimal. Leaf size=53 \[ \frac {2 C \tan ^{-1}\left (\frac {1-\frac {2 x}{\sqrt [3]{-\frac {a}{b}}}}{\sqrt {3}}\right )}{\sqrt {3} b}-\frac {C \log \left (\sqrt [3]{-\frac {a}{b}}+x\right )}{b} \]

[Out]

-C*ln((-a/b)^(1/3)+x)/b+2/3*C*arctan(1/3*(1-2*x/(-a/b)^(1/3))*3^(1/2))/b*3^(1/2)

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Rubi [A]  time = 0.08, antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {1867, 31, 617, 204} \[ \frac {2 C \tan ^{-1}\left (\frac {1-\frac {2 x}{\sqrt [3]{-\frac {a}{b}}}}{\sqrt {3}}\right )}{\sqrt {3} b}-\frac {C \log \left (\sqrt [3]{-\frac {a}{b}}+x\right )}{b} \]

Antiderivative was successfully verified.

[In]

Int[(2*(-(a/b))^(2/3)*C + C*x^2)/(a - b*x^3),x]

[Out]

(2*C*ArcTan[(1 - (2*x)/(-(a/b))^(1/3))/Sqrt[3]])/(Sqrt[3]*b) - (C*Log[(-(a/b))^(1/3) + x])/b

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 1867

Int[(P2_)/((a_) + (b_.)*(x_)^3), x_Symbol] :> With[{A = Coeff[P2, x, 0], B = Coeff[P2, x, 1], C = Coeff[P2, x,
2]}, With[{q = (a/b)^(1/3)}, Dist[C/b, Int[1/(q + x), x], x] + Dist[(B + C*q)/b, Int[1/(q^2 - q*x + x^2), x],
x]] /; EqQ[A - (a/b)^(1/3)*B - 2*(a/b)^(2/3)*C, 0]] /; FreeQ[{a, b}, x] && PolyQ[P2, x, 2]

Rubi steps

\begin {align*} \int \frac {2 \left (-\frac {a}{b}\right )^{2/3} C+C x^2}{a-b x^3} \, dx &=-\frac {C \int \frac {1}{\sqrt [3]{-\frac {a}{b}}+x} \, dx}{b}-\frac {\left (\sqrt [3]{-\frac {a}{b}} C\right ) \int \frac {1}{\left (-\frac {a}{b}\right )^{2/3}-\sqrt [3]{-\frac {a}{b}} x+x^2} \, dx}{b}\\ &=-\frac {C \log \left (\sqrt [3]{-\frac {a}{b}}+x\right )}{b}-\frac {(2 C) \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 x}{\sqrt [3]{-\frac {a}{b}}}\right )}{b}\\ &=\frac {2 C \tan ^{-1}\left (\frac {1-\frac {2 x}{\sqrt [3]{-\frac {a}{b}}}}{\sqrt {3}}\right )}{\sqrt {3} b}-\frac {C \log \left (\sqrt [3]{-\frac {a}{b}}+x\right )}{b}\\ \end {align*}

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Mathematica [B]  time = 0.10, size = 150, normalized size = 2.83 \[ \frac {C \left (b^{2/3} \left (-\frac {a}{b}\right )^{2/3} \log \left (a^{2/3}+\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )-a^{2/3} \log \left (a-b x^3\right )-2 b^{2/3} \left (-\frac {a}{b}\right )^{2/3} \log \left (\sqrt [3]{a}-\sqrt [3]{b} x\right )+2 \sqrt {3} b^{2/3} \left (-\frac {a}{b}\right )^{2/3} \tan ^{-1}\left (\frac {\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}+1}{\sqrt {3}}\right )\right )}{3 a^{2/3} b} \]

Antiderivative was successfully verified.

[In]

Integrate[(2*(-(a/b))^(2/3)*C + C*x^2)/(a - b*x^3),x]

[Out]

(C*(2*Sqrt[3]*(-(a/b))^(2/3)*b^(2/3)*ArcTan[(1 + (2*b^(1/3)*x)/a^(1/3))/Sqrt[3]] - 2*(-(a/b))^(2/3)*b^(2/3)*Lo
g[a^(1/3) - b^(1/3)*x] + (-(a/b))^(2/3)*b^(2/3)*Log[a^(2/3) + a^(1/3)*b^(1/3)*x + b^(2/3)*x^2] - a^(2/3)*Log[a
- b*x^3]))/(3*a^(2/3)*b)

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fricas [A]  time = 0.67, size = 53, normalized size = 1.00 \[ \frac {2 \, \sqrt {3} C \arctan \left (\frac {2 \, \sqrt {3} b x \left (-\frac {a}{b}\right )^{\frac {2}{3}} + \sqrt {3} a}{3 \, a}\right ) - 3 \, C \log \left (x + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*(-a/b)^(2/3)*C+C*x^2)/(-b*x^3+a),x, algorithm="fricas")

[Out]

1/3*(2*sqrt(3)*C*arctan(1/3*(2*sqrt(3)*b*x*(-a/b)^(2/3) + sqrt(3)*a)/a) - 3*C*log(x + (-a/b)^(1/3)))/b

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giac [B]  time = 0.22, size = 162, normalized size = 3.06 \[ -\frac {\sqrt {3} {\left (a b^{2} - \sqrt {3} \sqrt {a^{2} b^{4}} i\right )} C \arctan \left (\frac {\sqrt {3} {\left (2 \, x + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{3 \, a b^{3}} - \frac {{\left (C b^{2} \left (\frac {a}{b}\right )^{\frac {2}{3}} + 2 \, \left (-a b^{2}\right )^{\frac {2}{3}} C\right )} \left (\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x - \left (\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{3 \, a b^{2}} - \frac {{\left (3 \, a b^{2} - \sqrt {3} \sqrt {a^{2} b^{4}} i\right )} C \log \left (x^{2} + x \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 \, a b^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*(-a/b)^(2/3)*C+C*x^2)/(-b*x^3+a),x, algorithm="giac")

[Out]

-1/3*sqrt(3)*(a*b^2 - sqrt(3)*sqrt(a^2*b^4)*i)*C*arctan(1/3*sqrt(3)*(2*x + (a/b)^(1/3))/(a/b)^(1/3))/(a*b^3) -
1/3*(C*b^2*(a/b)^(2/3) + 2*(-a*b^2)^(2/3)*C)*(a/b)^(1/3)*log(abs(x - (a/b)^(1/3)))/(a*b^2) - 1/6*(3*a*b^2 - s
qrt(3)*sqrt(a^2*b^4)*i)*C*log(x^2 + x*(a/b)^(1/3) + (a/b)^(2/3))/(a*b^3)

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maple [B]  time = 0.05, size = 135, normalized size = 2.55 \[ \frac {2 \left (-\frac {a}{b}\right )^{\frac {2}{3}} \sqrt {3}\, C \arctan \left (\frac {\left (\frac {2 x}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}+1\right ) \sqrt {3}}{3}\right )}{3 \left (\frac {a}{b}\right )^{\frac {2}{3}} b}-\frac {2 \left (-\frac {a}{b}\right )^{\frac {2}{3}} C \ln \left (x -\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {2}{3}} b}+\frac {\left (-\frac {a}{b}\right )^{\frac {2}{3}} C \ln \left (x^{2}+\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {2}{3}} b}-\frac {C \ln \left (b \,x^{3}-a \right )}{3 b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*(-a/b)^(2/3)*C+C*x^2)/(-b*x^3+a),x)

[Out]

-2/3*C*(-a/b)^(2/3)/b/(a/b)^(2/3)*ln(x-(a/b)^(1/3))+1/3*C*(-a/b)^(2/3)/b/(a/b)^(2/3)*ln(x^2+(a/b)^(1/3)*x+(a/b
)^(2/3))+2/3*C*(-a/b)^(2/3)/b/(a/b)^(2/3)*3^(1/2)*arctan(1/3*(1+2/(a/b)^(1/3)*x)*3^(1/2))-1/3*C/b*ln(b*x^3-a)

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maxima [B]  time = 3.03, size = 167, normalized size = 3.15 \[ -\frac {2 \, \sqrt {3} {\left (C a - {\left (3 \, C \left (\frac {a}{b}\right )^{\frac {1}{3}} \left (-\frac {a}{b}\right )^{\frac {2}{3}} + \frac {C a}{b}\right )} b\right )} \arctan \left (\frac {\sqrt {3} {\left (2 \, x + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{9 \, a b} - \frac {{\left (C \left (\frac {a}{b}\right )^{\frac {2}{3}} - C \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )} \log \left (x^{2} + x \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{3 \, b \left (\frac {a}{b}\right )^{\frac {2}{3}}} - \frac {{\left (C \left (\frac {a}{b}\right )^{\frac {2}{3}} + 2 \, C \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )} \log \left (x - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \, b \left (\frac {a}{b}\right )^{\frac {2}{3}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*(-a/b)^(2/3)*C+C*x^2)/(-b*x^3+a),x, algorithm="maxima")

[Out]

-2/9*sqrt(3)*(C*a - (3*C*(a/b)^(1/3)*(-a/b)^(2/3) + C*a/b)*b)*arctan(1/3*sqrt(3)*(2*x + (a/b)^(1/3))/(a/b)^(1/
3))/(a*b) - 1/3*(C*(a/b)^(2/3) - C*(-a/b)^(2/3))*log(x^2 + x*(a/b)^(1/3) + (a/b)^(2/3))/(b*(a/b)^(2/3)) - 1/3*
(C*(a/b)^(2/3) + 2*C*(-a/b)^(2/3))*log(x - (a/b)^(1/3))/(b*(a/b)^(2/3))

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mupad [B]  time = 5.40, size = 172, normalized size = 3.25 \[ \sum _{k=1}^3\ln \left (-\frac {\left (C+\mathrm {root}\left (27\,a^2\,b^3\,z^3+27\,C\,a^2\,b^2\,z^2+9\,C^2\,a^2\,b\,z+9\,C^3\,a^2,z,k\right )\,b\,3\right )\,\left (C\,a+\mathrm {root}\left (27\,a^2\,b^3\,z^3+27\,C\,a^2\,b^2\,z^2+9\,C^2\,a^2\,b\,z+9\,C^3\,a^2,z,k\right )\,a\,b\,3+2\,C\,b\,x\,{\left (-\frac {a}{b}\right )}^{2/3}\right )}{b^3}\right )\,\mathrm {root}\left (27\,a^2\,b^3\,z^3+27\,C\,a^2\,b^2\,z^2+9\,C^2\,a^2\,b\,z+9\,C^3\,a^2,z,k\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((C*x^2 + 2*C*(-a/b)^(2/3))/(a - b*x^3),x)

[Out]

symsum(log(-((C + 3*root(27*a^2*b^3*z^3 + 27*C*a^2*b^2*z^2 + 9*C^2*a^2*b*z + 9*C^3*a^2, z, k)*b)*(C*a + 3*root
(27*a^2*b^3*z^3 + 27*C*a^2*b^2*z^2 + 9*C^2*a^2*b*z + 9*C^3*a^2, z, k)*a*b + 2*C*b*x*(-a/b)^(2/3)))/b^3)*root(2
7*a^2*b^3*z^3 + 27*C*a^2*b^2*z^2 + 9*C^2*a^2*b*z + 9*C^3*a^2, z, k), k, 1, 3)

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sympy [C]  time = 0.84, size = 110, normalized size = 2.08 \[ - \frac {C \left (\log {\left (- \frac {a}{b \left (- \frac {a}{b}\right )^{\frac {2}{3}}} + x \right )} + \frac {\sqrt {3} i \log {\left (\frac {a}{2 b \left (- \frac {a}{b}\right )^{\frac {2}{3}}} - \frac {\sqrt {3} i a}{2 b \left (- \frac {a}{b}\right )^{\frac {2}{3}}} + x \right )}}{3} - \frac {\sqrt {3} i \log {\left (\frac {a}{2 b \left (- \frac {a}{b}\right )^{\frac {2}{3}}} + \frac {\sqrt {3} i a}{2 b \left (- \frac {a}{b}\right )^{\frac {2}{3}}} + x \right )}}{3}\right )}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*(-a/b)**(2/3)*C+C*x**2)/(-b*x**3+a),x)

[Out]

-C*(log(-a/(b*(-a/b)**(2/3)) + x) + sqrt(3)*I*log(a/(2*b*(-a/b)**(2/3)) - sqrt(3)*I*a/(2*b*(-a/b)**(2/3)) + x)
/3 - sqrt(3)*I*log(a/(2*b*(-a/b)**(2/3)) + sqrt(3)*I*a/(2*b*(-a/b)**(2/3)) + x)/3)/b

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